#f (x) = sin ^ 3x #, # D_f = RR #
#g (x) = sqrt (3x-1) #, # Dg = 1/3, + oo) #
#D_ (sương mù) = {## AAx ##trong##RR: ## x ##trong## D_g #, #g (x) ##trong##D_f} #
#x> = 1/3 #, #sqrt (3x-1) ##trong## RR # #-># # x ##trong## 1/3, + oo) #
# AAx ##trong## 1/3, + oo) #,
- # (sương mù) '(x) = f' (g (x)) g '(x) = f' (sqrt (3x-1)) ((3x-1) ') / (2sqrt (3x-1)) #
#f '(x) = 3 giây ^ 2x (sinx)' = 3 giây ^ 2xcosx #
vì thế # (sương mù) '(x) = sin ^ 2 (sqrt (3x-1)) cos (sqrt (3x-1)) * 9 / (2sqrt (3x-1)) #
